Respuesta :

[tex]\dfrac{1}{3}=n+ \dfrac{3}{4}[/tex]

[tex]n = \dfrac{1}{3} -\dfrac{3}{4} [/tex]

[tex]n = \dfrac{1 \times 4}{3 \times 4} -\dfrac{3 \times 3}{4 \times3} [/tex]

[tex]n = \dfrac{4}{12} -\dfrac{9}{12} [/tex]

[tex]n = -\dfrac{5}{12} [/tex]

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