The perimeter of a rectangle is twice the sum of its length and its width. The perimete is 28 meters and its length is 2 meters more than twice its width. What is its length?
Let l be length and w be width. So the problem already gave you what a perimeter is, which is 2l + 2w. Now it says perimeter is 28, so 2l + 2w = 28. Then it says length is 2 more than twice its width, so l = 2w + 2. Now substitute. 2(2w + 2) + 2w = 28 4w + 4 + 2w = 28 6w = 24 w = 4
Now substitute w back in l = 2w + 2 l = 2(4) + 2 l = 10
