fbcvn
fbcvn
02-10-2016
Mathematics
contestada
Verify the identity.
cot^2x/ cscx-1 = 1+sinx/sinx
Respuesta :
Maria81
Maria81
02-10-2016
cot²x /(cscx + 1) = (1 - sinx) /sinx
let's apply the identity cot²x = csc²x - 1:
(csc²x - 1) /(cscx + 1) = (1 - sinx) /sinx
(factoring csc²x - 1 as a difference of squares and then simplifying)
[(cscx + 1)(cscx - 1)] /(cscx + 1) = (1 - sinx) /sinx
cscx - 1 = (1 - sinx) /sinx
let's recall that cscx = 1 /sinx:
(1 /sinx) - 1 = (1 - sinx) /sinx
ending with:
(1 - sinx) /sinx = (1 - sinx) /sinx (verified)
I hope it helps
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