cabri2a2ErlTiya
cabri2a2ErlTiya cabri2a2ErlTiya
  • 04-08-2016
  • Mathematics
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find the product of (4x − 3)(2x^2 − 7x 1). 8x^3 − 22x^2 17x− 3 8x^3 8x^2 4x − 3 8x^3 − 34x^2 25x − 3 8x^3 − 42x^2 25x − 3

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nobillionaireNobley
nobillionaireNobley nobillionaireNobley
  • 04-08-2016
(4x - 3)(2x^2 - 7x + 1) = 4x(2x^2 - 7x + 1) - 3(2x^2 - 7x + 1) = 8x^3 - 28x^2 + 4x - 6x^2 + 21x - 3 = 8x^3 - 34x^2 + 25x - 3
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