rahhh9hhhGalexan rahhh9hhhGalexan

04-08-2016
Chemistry

contestada

Solve for the final temperature of the mixture of 400.0 mL of water at 25.00 °C and add 140.0 mL of water at 95.00 °C. Use 1.00 g/mL as the density of water.

Respuesta :

meerkat18 meerkat18

07-08-2016

(mass)(ΔT)(Cs) = (Cs)(ΔT)(mass)
(140.0g)(95.00−x)(4.184)=(4.184)(x−25.00)(400.0g)
Solve for x
55647.2 - 585.76x = 1673.6x – 41840
-585.76x – 1673.6x = -41840 – 55647.2
-2,259.36x = -97,487.2
-2,259.36x / -2,259.36 = -97,487.2 / -2,259.36
X = 43.15

Answer Link

Otras preguntas

There are no tickets available on this day. I wish I ___ them in advance

From the readings, powerpoint presentation, and video clips, write a 200-300 word essay answering the following questions. What were the factors that led to the

Which of the following is NOT a conjugate acid-base pair? Which of the following is NOT a conjugate acid-base pair? a.H2SO3/HSO3b.NH4+NH3 c.C2H3O2d.HC2H3O2 H3O+

Rewrite 3x-y=-4 in slope-intercept form

Find the exact value of each expression. DO NOT use a calculator. sin 22π/3

What is bondage and discipline? (B-D)

what kind of code defines where text breaks to a new paragraph? a) html tag b) css property c) server-side script d) client-side script

No separation via recrystallization can ever be achieved between two solid substances that have the same solubility in all solvents at all temperatures. a) Tru

Interior and exterior angles

Explain a strategy you can use to compare 2/6 & 5/8