hollandjo hollandjo
  • 03-03-2020
  • Mathematics
contestada

factor q^2+q+5pq+5p by grouping

Respuesta :

profarouk profarouk
  • 08-03-2022

Answer:

(q + 1)(q + 5p)

Step-by-step explanation:

q² + q + 5pq + 5p

= (q² + q) + (5pq + 5p)

Consider that : q² + q = q(q + 1) and 5pq + 5p = 5p(q + 1)

then

q² + q + 5pq + 5p 

= (q² + q) + (5pq + 5p) 

= q(q + 1) + 5p(q + 1)  

= (q + 1)(q + 5p)

Good luck :)

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