haamcsaai haamcsaai

04-04-2019
Mathematics

contestada

Prove this identity using the product-to-sum identity for sine:
[tex]sin^2x=\frac{1-cos(2x)}{2}[/tex]
umm pls

Respuesta :

LammettHash LammettHash

04-04-2019

It follows from

[tex]\cos2x=\cos(x+x)=\cos x\cos x-\sin x\sin x=\cos^2x-\sin^2x=1-2\sin^2x[/tex]

[tex]\implies\cos 2x-1=-2\sin^2x[/tex]

[tex]\implies\sin^2x=\dfrac{1-\cos2x}2[/tex]

Answer Link

Otras preguntas

Which expression is a factor of both x^2 − 9 and x^2 + 8 x + 15

To be fair, laws must be....... applied to all people. a) urgently b) vaguely c) uniformaly d) viably

food bill before tax:$45 sales tax:6.8% tip:24%

Y varies directly as x. If y=4 when x=16 find x when y = -2

Contribution in the cyber bullying movement

Which value of a would make the following expression completely factored x^2-a A)12 B)36 C)49 D)81

which is smallest medium and large

Drag the tiles to the correct boxes to complete the pairs Tiles ————————— equation expression variable linear solution exponent ————————— Pairs ————————— a quan

Which of the following lines is an example of anapest? 1. And the sheen of their spears was like stars on the sea, 2. Why so pale and wan, fond Lover? 3. Sha

What is six times six